python得到windows自启动列表的方法-创新互联

如下所示：

#!/usr/bin/python
#-*-coding:utf-8-*-
import _winreg as wr #导入内置的windows注册表操作库
import   os
from  socket import *
import getpass
def   GetStart():
    key = r'SOFTWARE\Microsoft\Windows\CurrentVersion\Run'
    aRegL = wr.ConnectRegistry(None,wr.HKEY_LOCAL_MACHINE)
    aRegC = wr.ConnectRegistry(None,wr.HKEY_CURRENT_USER)#getpass.getuser()为得到当前的用户名
    startdir = os.listdir(r'C:\Users'+ os.sep + getpass.getuser() + r'\AppData\Roaming\Microsoft\Windows\Start Menu\Programs\Startup')
    startExe = {'localmachine':[],'currentuser':[]}
    startExe['startdir'] = startdir
    try:
      aKeyL = wr.OpenKey(aRegL,key)#打开键，返回句柄
      aKeyC = wr.OpenKey(aRegC,key)
      for i in range(1024):
        try:
          startExe['localmachine'].append( wr.EnumValue(aKeyL,i))
        except:
          break #异常就是终点,退出循环
      for i in range(1024):
        try:
          startExe['currentuser'].append( wr.EnumValue(aKeyC,i))
        except:
          break
    finally:
      wr.CloseKey(aKeyL)
      wr.CloseKey(aKeyC)
    return startExe
def   main():
    import sys
    reload(sys)
    sys.setdefaultencoding( "utf-8" )
    start = GetStart() #这个函数返回一个字典
    print 'LocalMachine'.center(50,'*')
    for i in start['localmachine']:#迭代字典中的数据
      print i
    print 'CurrentUser'.center(50,'*')
    for i in start['currentuser']:
      print i
    print 'StartUp dir'.center(50,'*')
    for i in start['startdir']:
      print i
if   __name__== "__main__":
    main()