Python实现模拟登录和登录跳转的方法-创新互联

Python实现模拟登录和登录跳转的方法？针对这个问题，这篇文章详细介绍了相对应的分析和解答，希望可以帮助更多想解决这个问题的小伙伴找到更简单易行的方法。

# coding:utf-8
import urllib
import urllib2
import cookielib
from bs4 import BeautifulSoup
# 设置登录url
login_url = "******************"
# 创建登录类
class Login(object):
  #初始化
  def __init__(self):
    self.username = ''
    self.password = ''
    # 验证码
    self.rode = ''
    #设置cookie
    self.cj = cookirlib,LWPCookieJar()
    self.opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(self.cj))
    urllib2.install_opener(self.opener)

  def setLoginInfo(self, username, passwoed ,rode):
    """设置登录用户信息"""
    self.username = username
    self.password = password
    self.rode = rode

  def login(self):
    """"模拟登录"""
    login_data = {'username': self.username, 'password': self.password, 'rode': self.rode}
    headers = {'User-Agent': 'Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/55.0.2859.0 Safari/537.36'}
    req = urllib2.Request(login_url, data=urllib.urlencode(login_data), headers=headers)
    response = urllibs.urlopen(req)
    # 加cookie, 自动保存seissionid,做后续跳转
    self.operate = self.opener.open(req)
    # 通过BeautifulSoup获取网页内容
    soup = BeautifulSoup(response, 'lxml')
    # 获取网页的content
    data = soup.select('#content')
    if data:
      print u'模拟登录成功!', data
    print u'模拟登录失败!'

  def skip(self, skip_url):
    """
    模拟登录成功后,跳转网页
    ----------------------------
    传递跳转网页的url
   """
    headers = {'User-Agent': 'Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/55.0.2859.0 Safari/537.36'}
    req = urllib2.Request(skip_url, headers=headers)
    response = urllib2.urlopen(req)
    soup = BeautifulSoup(response, 'lxml')
    # 获取跳转后网页的title
    print soup.title.string

if __name__ == "__main__":
  userlogin = Login()
  username = '***********'
  password = '***********'
  rode = '***********'
  # 执行模拟登录方法
  userlogin.login()
  # 执行模拟登录成功后网页跳转方法
  user_login.skip(skip_url = '***************')